WebThe locus of the centre of a circle which passes through the point (a,0) and touches the line x + 1 = 0, is A Circle B Ellipse C Parabola D Hyperbola Solution The correct option is C Parabola The locus is a parabola as distance of centre from straight line = its distance from point (a,0) Suggest Corrections 0 Similar questions Q. WebOct 24, 2016 · Explanation: The standard form for the equation of a circle is: (x −h)2 + (y −k)2 = r2 where (x,y) is any point on the circle, (h,k) is the center point and r is the radius. Use the standard form to write two equations using points A and B: ( − 2 − h)2 +(0 −k)2 = r2 (5 −h)2 + (1 − k)2 = r2 Because r2 = r2, we can set the left sides equal:
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WebA circle passes through (0,0) and (1,0) and touches the circle x 2+y 2=9 , then the centre of circle is: Easy. View solution. WebThis formula tells us the shortest distance between a point (𝑥₁, 𝑦₁) and a line 𝑎𝑥 + 𝑏𝑦 + 𝑐 = 0. Since the radius is perpendicular to the tangent, the shortest distance between the center and … birthe borup
Let C be the circle with center at (1,1) and radius = 1 . If T is the
WebJan 12, 2024 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features NFL Sunday Ticket … WebThis means that, using Pythagoras’ theorem, the equation of a circle with radius r and centre (0, 0) is given by the formula \ (x^2 + y^2 = r^2\). Example Find the equation of a circle... WebMar 16, 2024 · Transcript. Ex 11.1, 5 Find the equation of the circle with centre (–a, –b) & radius √ (a2 −b2) We know that equation of a circle is (x – h)2 + (y – k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = (−a, −b) So h = −a & k = −b & Radius r = √ (a2 −b2) . Putting values in (1) (x − (−a))2 ... birthe bovin